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The area of Saikhowa National Park is approximately

The area of Saikhowa National Park is approximately

(a) 920 sq. km

(b) 530 sq. km

(c) 650 sq. Km

(d) None of These

Answer: 650 sq. Km

Assam Geography Mcqs and Answers

Explanation: Dibru-Saikhowa National Park is a national park located in Dibrugarh and Tinsukia districts, Assam, India.

It was designated a Biosphere Reserve in July 1997 with an area of 765 km2 (295 sq mi), including a core area of 340 km2 (130 sq mi) and a buffer zone of 425 km2 (164 sq mi).

It is located at about 12 km (7.5 mi) north of Tinsukia town at an average elevation of 118 m (387 ft), ranging from 110 to 126 m (361 to 413 ft). The park is bounded by the Brahmaputra and Lohit Rivers in the north and Dibru River in the south.

It mainly consists of moist mixed semi-evergreen forests, moist mixed deciduous forests, canebrakes and grasslands. It is the largest salix swamp forest in north-eastern India, with a tropical monsoon climate with a hot and wet summer and cool and usually dry winter.

Annual rainfall ranges from 2,300 to 3,800 mm (91 to 150 in). It is a haven for many endangered species and rich in fish diversity. In December 2020, Gauhati highcourt stayed a permission given to Oil India Limited for hydrocarbon exploration at seven locations inside the protected area.

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